[vlc-devel] Deadlocked in stop if too close to play

[jboileau]

Hi Pierre,

I will create a simple application to re-create the problem using
samples from your site. This will have two benefits: Maybe I'll have
something simple to give you and maybe a different aproach will show a
flaw in my own application. If I end up with something simple that
works I can then extrapolate for my application. Hopefully its simply
a misunderstanding on my part on how to use the API.

Thanks for helping out! I will get back to you with more details as
soon as I can.

Jacques



On Tue, Oct 27, 2009 at 7:48 AM, Pierre d'Herbemont <pdherbemont at free.fr> wrote:
> On Mon, Oct 26, 2009 at 5:42 PM, jboileau <jboileau at gmail.com> wrote:
>> Hi,
>>
>> I am using LibVLC in an application of my own under Win32. One problem
>> I have never been able to fix is a deadlock in
>> libvlc_media_player_stop if it is called too close to a
>> libvlc_media_player_play. The application hangs and pausing the
>> application in the development environment reveals that it is
>> deadlocked in the stop.
>
> Can you share with us a sample code that exhibit this bug?
>
>> My application cycles through surveillance cameras using a timer, but
>> on an emergency signal I must switch to a particular camera. As you
>> may deduce: a play may have just been started when such a signal is
>> received. Thus a stop may be very close to a play.
>>
>> I guess, to the limit, this code should work and not hang once in a while:
>>
>> libvlc_media_player_play(aLibVLCMediaPlayer, &lLibVLCException);
>> libvlc_media_player_stop(aLibVLCMediaPlayer, &lLibVLCException);
>>
>> but it does at least 10% of the time for me. I have pasted below what
>> little stack trace info I get from Visual Studio after the stop is
>> called. What baffles me is that it seems to show that the stop calls
>> libvlc_media_get_user_data. Looking at the VLC source code I could not
>> find this. libvlc_media_player_stop does not seem to call
>> libvlc_media_get_user_data!?!!?
>
> The stack is then What version of libvlc/vlc are you using?
>
> This could be three things:
> - a bug in your program
> - a bug in libvlc
> - a bug in libvlccore

Hopefully its simply a misunderstanding on my part on how to use the
API. Thanks for helping out! I will get back to you with more details
as soon as I

>
> We have to clear this out. And the way to clear that is to show that
> it is not in your program (ie - doing stuff in the handler
> synchronously where libvlc doesn't support it well). For that the
> sample test code would be great.
>
> Pierre.
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